Posted Date:08-05-2017

In this post we will explain how to dropdown list dynamically using html,php

First we explain dynamic dropdown list using php

Dynamic dropdown list using php

Step 1: Create a new file dropdown.php

step 2:  Create a mysql connection code inside dropdown.php

$mysqlserver="localhost";
$mysqlusername="root";
$mysqlpassword="";
$link=mysql_connect($mysqlserver, $mysqlusername, $mysqlpassword) or die ("Error connecting to mysql server: ".mysql_error());
$dbname = 'test';
mysql_select_db($dbname, $link) or die ("Error selecting specified database on mysql server: ".mysql_error());

stp3 : Create mysql table ls_countries

CREATE TABLE `ls_countries` (  `country_id` int(11) NOT NULL AUTO_INCREMENT,  `sortname` varchar(3) NOT NULL,  `name` varchar(150) NOT NULL,  `phonecode` int(11) NOT NULL,  `status` int(11) NOT NULL COMMENT '1->active,0->deactive',  PRIMARY KEY (`country_id`)) ENGINE=InnoDB AUTO_INCREMENT=247 DEFAULT CHARSET=utf8

 

step4 : Create drop down list dynamically using following code

<select>
  <option>Select Country</option>
  <?php
   $cdquery="SELECT * FROM ls_countries";
            $cdresult=mysql_query($cdquery) or die ("Query to get data from firsttable failed: ".mysql_error());
            
            while ($cdrow=mysql_fetch_array($cdresult)) {
            $cdTitle=$cdrow["name"];
                echo "<option>$cdTitle </option>";
            
            }
  ?>
</select>

we are  following above steps and getting code like this

<?php 
$mysqlserver="localhost";
$mysqlusername="root";
$mysqlpassword="";
$link=mysql_connect($mysqlserver, $mysqlusername, $mysqlpassword) or die ("Error connecting to mysql server: ".mysql_error());
$dbname = 'linus';
mysql_select_db($dbname, $link) or die ("Error selecting specified database on mysql server: ".mysql_error());
?>
<!DOCTYPE html>
<html>
<head>
  <title>Drop Down Using Php</title>
</head>
<body>
<select>
  <option>Select Country</option>
  <?php
   $cdquery="SELECT * FROM ls_countries";
            $cdresult=mysql_query($cdquery) or die ("Query to get data from firsttable failed: ".mysql_error());
            
            while ($cdrow=mysql_fetch_array($cdresult)) {
            $cdTitle=$cdrow["name"];
                echo "<option>$cdTitle </option>";
            
            }
  ?>
</select>
</body>
</html>

 

 

 

 

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